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MODEL PAPER 10 — Chemistry STD 12 Science — Question

Rajasthan BoardEnglish MediumSTD 12 ScienceChemistryMODEL PAPER 105 Marks
Question
$FeSO_4$ solution mixed with $\left( NH _4\right)_2 SO _4$ solution in $1:1$ molar ratio gives the test of $Fe ^{2+}$ ion but $CuSO _4$ solution mixed with aqueous ammonia in $1: 4$ molar ratio does not give the test of $Cu ^{2+}$ ion. Explain why?
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Answer

$\ce{\left( NH _4\right)_2 SO _4+ FeSO _4+6 H _2 O \rightarrow FeSO _4 \cdot\left( NH _4\right)_2 SO _4 \cdot 6 H _2 O} ($Mohr's Salt$)$
$\ce{CuSO _4+4 NH _3+5 H _2 O \rightarrow\left[ Cu \left( NH _3\right)_4\right] SO _4 \cdot 5 H _2 O} ($tetramminocopper$(ii)$ sulphate)
Both the compounds i.e., $\ce{FeSO _4 \cdot\left( NH _4\right)_2 SO _4 \cdot 6 H _2 O}$ and $\ce{\left[ Cu \left( NH _3\right)_4\right] SO _4 \cdot 5 H _2 O}$ fall under the category of addition compounds with only one major difference
i.e., the former is an example of a double salt, while the latter is a coordination compound. A double salt is an addition compound that is stable in the solid state but that which breaks up into its constituent ions in the dissolved state. These compounds exhibit individual properties of their constituents. For e.g. $\ce{FeSO _4 \cdot\left( NH _4\right)_2 SO _4 \cdot 6 H _2 O}$ breaks into $\ce{Fe ^{2+}, NH ^{4+}$ and $SO _4{ }^{2-}}$ ions.
Hence, it gives a positive test for $\ce{Fe ^{2+}}$ ions.A coordination compound is an addition compound which retains its identity in the solid as well as in the dissolved state. However, the individual properties of the constituents are lost.
 This happens because $\ce{\left[ Cu \left( NH _3\right)_4\right] SO _4 .5 H _2 O}$ does not show the test for $\ce{Cu ^{2+}}$. The ions present in the solution of $\ce{\left[ Cu \left( NH _3\right)_4\right] SO _4 \cdot 5 H _2 O}$ are $\ce{\left[ Cu \left( NH _3\right)_4\right]^{2+}$ and $SO _4{ }^{2-}}$.

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