For, $ns$ - orbital total number of nodes $=n-1$
where angular nodes $=l$ and number of radial nodes $=n-l-1$
Thus, the total number of nodes is given $=$ angular nodes $+$ radial nodes $= n -l-1+l=n-1$
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$2\left[ Au ( CN )_2\right]_{( aq )}^{-}+ Zn ( s ) \rightarrow 2 Au ( s )+\left[ Zn ( CN )_4\right]_{( aq )}^{2-}$
$A.$ Redox reaction
$B.$ Displacement reaction
$C.$ Decomposition reaction
$D.$ Combination reaction
Choose the correct answer from the options given below:
$kJ\,mol ^{-1}$ (Nearest integer)
Given : $\Delta_{ dis } H _{ Cl _{2(g)}}^{\circ}=240\,kJ\,mol ^{-1}$.
$\Delta_{ eg } H _{ Cl _{(g)}}^{\circ}=-350\,kJ\,mol ^{-1}$,
$\Delta_{ hyd } H _{ Cl i _{( j )}^{\circ}}^{\circ}=-380\,kJ\,mol ^{-1}$
| $List-I$ | $List-II$ |
| $A$ $\left( NH _{4}\right)_{2} Cr _{2} O _{7} \stackrel{\Delta}{\longrightarrow}$ | $I$ $H _{2}$ |
| $B$ $KMnO _{4}+ HCl \rightarrow$ | $II$ $N _{2}$ |
| $C$ $Al + NaOH + H _{2} O \rightarrow$ | $III$ ${ O _{2}}$ |
| $D$ $NaNO _{3} \stackrel{\Delta}{\longrightarrow}$ | $IV$ ${ Cl _{2}}$ |
Choose the correct answer from the options given below.