
- Will remain zero.
- Will become positive.
- Will become neagative.
- Will become undefined.

Explanation:
Charge distribution:

Due to charge distribution, intersection by the closed surface of conducting sphere containing the positive charge. So we can say that the flux of the electric field through the closed surface will become positive.
$\therefore\phi=\frac{\text{q}_{\text{in}}}{\in_0}\Rightarrow+\text{ve}$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

$A$: standing on the horizontal surface
$B$: standing on the block According to the observer $A$
Assertion (A) : The moment of inertia of a rigid body reduces to its minimum value as compared to any other parallel axis when the axis of rotation passes through its centre of mass.
Reason (R): The weight of a rigid body always acts through its centre of mass in uniform gravitational field. Of these statements: