Explanation:
Charge distribution:
Due to charge distribution, intersection by the closed surface of conducting sphere containing the positive charge. So we can say that the flux of the electric field through the closed surface will become positive.
$\therefore\phi=\frac{\text{q}_{\text{in}}}{\in_0}\Rightarrow+\text{ve}$
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An electron makes a transition from orbit n = 4 to the orbit n = 2 of a hydrogen atom. The wave number of the emitted radiations (R = Rydberg's constant) will be
|
(a) |
(b) |
(c) |
(d) |
The particles which can be added to the nucleus of an atom without changing its chemical properties are called
|
(a) Electrons |
(b) Protons |
(c) Neutrons |
(d) None of the above |
The capacitance between the points A and B in the given circuit will be
|
(a) 1 μF |
(b) 2 μF |
(c) 3 μF |
(d) 4 μF |
The fraction f of radioactive material that has decayed in time t, varies with time t. The correct variation is given by the curve
|
(a) A |
(b) B |
(c) C |
(d) D |
Which of the following wavelength falls in X-ray region
|
(a) 10000 Å |
(b) 1000 Å |
(c) 1 Å |
(d) 10–2 Å |
