Question
Fill in the blanks.$\frac{-7}{9}+\dots=3$
✓
Answer
$\frac{-7}{9}+\frac{34}{9}=3$Solution:
$\frac{-7}{9}+\text{x}=3$ $\Rightarrow\text{x}=3-\frac{-7}{9}$ $\Rightarrow\text{x}=\frac{3\times9}{1\times9}-\frac{-7}{9}$ $\Rightarrow\text{x}=\frac{27}{9}-\frac{7}{9}$ $\Rightarrow\text{x}=\frac{27+7}{9}$ $\Rightarrow\text{x}=\frac{34}{9}$ $\frac{-7}{9}+\frac{34}{9}=3$
$\frac{-7}{9}+\text{x}=3$ $\Rightarrow\text{x}=3-\frac{-7}{9}$ $\Rightarrow\text{x}=\frac{3\times9}{1\times9}-\frac{-7}{9}$ $\Rightarrow\text{x}=\frac{27}{9}-\frac{7}{9}$ $\Rightarrow\text{x}=\frac{27+7}{9}$ $\Rightarrow\text{x}=\frac{34}{9}$ $\frac{-7}{9}+\frac{34}{9}=3$
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