Question
Fill in the blanks:
$9\frac{2}{3}+\ ....=19$
$9\frac{2}{3}+\ ....=19$
✓
Answer
$9\frac{2}{3}+9\frac{1}{3}=19$Solution:
Given, $9\frac{2}{3}+\ ....=19$ Let the value in the blank be x. $9\frac{2}{3}+\text{x}=19$ $\Rightarrow\text{x}=19-9\frac{2}{3}$ $\Rightarrow\text{x}=\frac{19}{1}-\frac{9\times3+2}{3}$ $\Rightarrow\text{x}=\frac{19}{1}-\frac{29}{3}$ $\Rightarrow\text{x}=\frac{19\times3}{1\times3}-\frac{29\times1}{3\times1}$ (because LCM of 1 and 3 is 3) $\Rightarrow\text{x}=\frac{57}{3}-\frac{29}{3}$ $\Rightarrow\text{x}=\frac{57-29}{3}$ $\Rightarrow\text{x}=\frac{28}{3}$ $\text{x}=9\frac{1}{3}$
Given, $9\frac{2}{3}+\ ....=19$ Let the value in the blank be x. $9\frac{2}{3}+\text{x}=19$ $\Rightarrow\text{x}=19-9\frac{2}{3}$ $\Rightarrow\text{x}=\frac{19}{1}-\frac{9\times3+2}{3}$ $\Rightarrow\text{x}=\frac{19}{1}-\frac{29}{3}$ $\Rightarrow\text{x}=\frac{19\times3}{1\times3}-\frac{29\times1}{3\times1}$ (because LCM of 1 and 3 is 3) $\Rightarrow\text{x}=\frac{57}{3}-\frac{29}{3}$ $\Rightarrow\text{x}=\frac{57-29}{3}$ $\Rightarrow\text{x}=\frac{28}{3}$ $\text{x}=9\frac{1}{3}$
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