Question
Fill in the blanks.
If $e_1, e_2, e_3, e_4 $ are the four elementary outcomes in a sample space and $P(e_1) = 0.1, P(e_2) = 0.5, P (e_3) = 0.1,$ then the probability of $e_4 $ is ___________.

Answer

If $e_1, e_2, e_3, e_4 $ are the four elementary outcomes in a sample space and $P(e_1) = 0.1, P(e_2) = 0.5, P (e_3) = 0.1,$ then the probability of $e_4 $ is $0.3$
Solution:
$\text{P}(\text{E}_1)+\text{P}(\text{E}_2)+\text{P}(\text{E}_3)+\text{P}(\text{E}_4)=1$
$\Rightarrow0.1+0.5+0.1+\text{P}(\text{E}_4)=1$
$\Rightarrow0.7+\text{P}(\text{E}_4)=1$
 $\therefore\ \text{P}(\text{E}_4)=0.3$

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