Fill in the blanks in the following table: P(A) P(B) P( A B ) P( A B ) (i) 1 3 1 5 1 15 ....... (ii) 0.35 .... 0.25 0.6 (iii) 0.5 0.35 .... 0.7

1. Given, P(A) =1 3 , P(A )=1 15 P(B) =1 5 , P(A )= ....... (A )=P(A)+P(B)-P(A ) =1 3 +1 5 -1 15 =5+3-1 15 =8-1 15 =7 15 (A )=7 15 2. Given, P(A) = 0.35, P(B) = .... P(A )=0.25, P(A )=0.6 (A )=P(A)+P(B)-P(A ) 0.6=0.35+P(B)-0.25 0.6=0.10+P(B) P(B)=0.6-0.1 P(B)=0.5 3. Given P(A) = 0.5, P(B) = 0.35 P(A )= ..., P(A )=0.7 (A )=P(A)+P(B)-P(A ) 0.7=0.5+0.35-P(A ) 0.7=0.85-P(A ) P(A )=0.85-0.7 P(A )=0.15

Fill in the blanks in the following table: P(A) P(B) P( A B ) P( …

Download App

Question

Fill in the blanks in the following table:

	P(A)	P(B)	$\text{P}({\text{A}}\cap{\text{B}})$	$\text{P}({\text{A}}\cup{\text{B}})$
(i)	$\frac{1}{3}$	$\frac{1}{5}$	$\frac{1}{15}$	.......
(ii)	0.35	....	0.25	0.6
(iii)	0.5	0.35	....	0.7

✓

Answer

Given,

P(A) $=\frac{1}{3},\ \text{P}(\text{A}\cap\text{B})=\frac{1}{15}$

P(B) $=\frac{1}{5},\ \text{P}(\text{A}\cup\text{B})=\ .......$

$\because\text{P}(\text{A}\cup\text{B})=\text{P}(\text{A})+\text{P}(\text{B})-\text{P}(\text{A}\cap\text{B})$

$=\frac{1}{3}+\frac{1}{5}-\frac{1}{15}$

$=\frac{5+3-1}{15}$

$=\frac{8-1}{15}=\frac{7}{15}$

$\because\text{P}(\text{A}\cup\text{B})=\frac{7}{15}$

Given,

P(A) = 0.35, P(B) = ....

$\text{P}(\text{A}\cap\text{B})=0.25,\ \text{P}(\text{A}\cup\text{B})=0.6$

$\because\text{P}(\text{A}\cup\text{B})=\text{P}(\text{A})+\text{P}(\text{B})-\text{P}(\text{A}\cap\text{B})$

$0.6=0.35+\text{P}(\text{B})-0.25$

$0.6=0.10+\text{P}(\text{B})$

$\text{P}(\text{B})=0.6-0.1$

$\text{P}(\text{B})=0.5$

Given

P(A) = 0.5, P(B) = 0.35

$\text{P}(\text{A}\cap\text{B})=\ ...,\ \text{P}(\text{A}\cup\text{B})=0.7$

$\because\text{P}(\text{A}\cup\text{B})=\text{P}(\text{A})+\text{P}(\text{B})-\text{P}(\text{A}\cap\text{B})$

$0.7=0.5+0.35-\text{P}(\text{A}\cap\text{B})$

$0.7=0.85-\text{P}(\text{A}\cap\text{B})$

$\text{P}(\text{A}\cap\text{B})=0.85-0.7$

$\text{P}(\text{A}\cap\text{B})=0.15$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "Solve the Following Question.(2 Marks)" from Probability→Probability — all question types→Maths STD 11 Science question papers→Maharashtra Board STD 11 Science question papers→Maharashtra Board question paper generator→

Probability — Maths STD 11 Science — Question

Answer

Need a full question paper?

Explore more

Similar questions