Question
Fill in the blanks.
In $\triangle ABC$, if $\angle A =90^{\circ}$, then $BC ^2$ = (___) + (___).

Answer

In $\triangle ABC$, if $\angle A =90^{\circ}$, then: $BC ^2=(\underline{ AB })^2+( AC )^2$
Solution:
In $\triangle ABC$, if $\angle A =90^{\circ}$, then by pythagoras theoram:
$BC^2=AB^2+AC^2$

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