Question
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Answer
We have, $144 \times 2^{-3}=\frac{144}{2^3}=\frac{12 \times 12}{2 \times 2 \times 2}=18$
Now, $\quad 18 \times 12^{-1}=\frac{18}{12}=\frac{3}{2}$
Again, $\quad \frac{3}{2} \times 3^{-2}=\frac{3}{2} \times \frac{1}{3^2}=\frac{1}{6}$
Now, $\quad 18 \times 12^{-1}=\frac{18}{12}=\frac{3}{2}$
Again, $\quad \frac{3}{2} \times 3^{-2}=\frac{3}{2} \times \frac{1}{3^2}=\frac{1}{6}$
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