Question
Find $(–13) + 32 – 8 – 1$

Answer

$(–13) + 32 – 8 – 1$
$= (–13) + 32 – 9$
$= (–13) + 32 +$ (additive inverse of $9)$
$= (–13) + 32 + (–9)$
$= (–13) + 23 + 9 + (–9)$
$= (–13) + 23 + 0$
$= (–13) +23$
$= (–13) + 13 + 10$
$= 0 + 10 = 10$

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