Question
Find: 18th term of the A.P. $\sqrt{2},\ 3\sqrt{2},\ 5\sqrt{2},\ ...$

Answer

To find 18th term of A.P. $\sqrt{2},3\sqrt{2},5\sqrt{2},\ ...$
Here, 1st term $\text{a}_1=\sqrt{2}$
and d = cpmmon difference $=2\sqrt{2}$
$\therefore\text{a}_\text{n}=\text{a}_1+(\text{n}-1)\text{d}$
$\text{a}_{18}=\sqrt{2}+2\sqrt{2}(17)=35\sqrt{2}$

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