Question
Find $-2 \frac{1}{9}-6$
✓
Answer
$-2 \frac{1}{9}-6=\frac{-19}{9}-6$
=$\frac{-19}{9}+(-6)=\frac{-19}{9}+\frac{(-6)}{1}$
$LCM$ of $9$ and $1$ is $9.$
$-6\over 1$=$-6\times9\over 1 \times 9$=$-54\over 9$
Thus, $\frac{-19}{9}+\frac{(-6)}{1}=\frac{-19}{9}+\frac{(-54)}{9}$
$\frac{-19+(-54)}{9}=\frac{-73}{9}=-8 \frac{1}{9}$
=$\frac{-19}{9}+(-6)=\frac{-19}{9}+\frac{(-6)}{1}$
$LCM$ of $9$ and $1$ is $9.$
$-6\over 1$=$-6\times9\over 1 \times 9$=$-54\over 9$
Thus, $\frac{-19}{9}+\frac{(-6)}{1}=\frac{-19}{9}+\frac{(-54)}{9}$
$\frac{-19+(-54)}{9}=\frac{-73}{9}=-8 \frac{1}{9}$
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