Question
Find $\frac{-3}{8}-\frac{7}{11}$
✓
Answer
$\frac{-3}{8}-\frac{7}{11}=\frac{-3}{8}+\left(\frac{-7}{11}\right)$
As denominators are different we find the LCM of 8 & 11
LCM of 8 and 11 is 88
$-3\over 8$ = $-3\times 11\over 8\times11$ = $-33\over 88$
$-7\over 11$ = $-7\times 8\over 11\times 8$ = $-56\over 88$
Thus, $\frac{-3}{8}+\frac{(-7)}{11}=\frac{-33}{88}+\frac{(-56)}{88}$
$\frac{-33+(-56)}{88}=\frac{-89}{88}=-1 \frac{1}{88}$
As denominators are different we find the LCM of 8 & 11
LCM of 8 and 11 is 88
$-3\over 8$ = $-3\times 11\over 8\times11$ = $-33\over 88$
$-7\over 11$ = $-7\times 8\over 11\times 8$ = $-56\over 88$
Thus, $\frac{-3}{8}+\frac{(-7)}{11}=\frac{-33}{88}+\frac{(-56)}{88}$
$\frac{-33+(-56)}{88}=\frac{-89}{88}=-1 \frac{1}{88}$
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