Question
Find a and b if : a + 2b + 2ai = 4 + 6i

Answer

a + 2b + 2ai = 4 + 6i Equating real and imaginary parts, we get a + 2b = 4 …..(i) 2a = 6 ……(ii) ∴ a = 3 Substituting, a = 3 in (i), we get 3 + 2b = 4
$\therefore b=\frac{1}{2}$
$\therefore a=3 \text { and } b=\frac{1}{2}$ Check:
For $a =3$ and $b =\frac{1}{2}$
Consider, L.H.S. = a + 2b + 2ai
$=3+2\left(\frac{1}{2}\right)+2(3) i$
= 4 + 6i = R.H.S.

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