Question
Find A as required:
The least number 567A is divisible by 3

Answer

A number is divisible by 3 if the sum of its digits is divisible by 3 Sum of digits of $567 A=5+6+7+A$
$
=18+ A
$
$\therefore 18$ is divisible by 3
$\therefore$ A maybe 0
The number will be 5670

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