Rajasthan BoardEnglish MediumSTD 11 ScienceMATHSModel Paper 102 Marks
Question
Find a point on the y-axis which is equidistant from A (-4, 3) and B(5, 2).
✓
Answer
Let the point on the y-axis be P(0, y) Here, it is given that P is equidistant from A(-4, 3) and B(5, 2). i.e., PA = PB $\Rightarrow \sqrt{(-4-0)^2+(3-y)^2}=\sqrt{(5-0)^2+(2-y)^2}$ Squaring both sides, we obtain $\begin{array}{l}\Rightarrow(-4-0)^2+(3-y)^2=(5-0)^2+(2-y)^2 \\ \Rightarrow 16+9-6 y+y^2=25+4-4 y+y^2 \\ \Rightarrow 25-6 y=29-4 y\end{array}$ $\begin{array}{l}\Rightarrow 2 y =-4 \\ \Rightarrow y =-2\end{array}$ Thus, the required point on the y-axis is (0, -2).
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