Question
Find $AD,$ if :
✓
Answer
From the right $\triangle ABE$
$\tan 45^{\circ}=\frac{ AE }{ BE }$
$1=\frac{ AE }{ BE }$
$AE = BE$
Therefore $AE = BE = 50\ m.$
Now from the rectangle $\text{BCDE}$ we have
$DE = BC = 10\ m.$
Therefore the length of $AD$ will be:
$AD = AE + DE = 50 + 10 = 60\ m.$
$\tan 45^{\circ}=\frac{ AE }{ BE }$
$1=\frac{ AE }{ BE }$
$AE = BE$
Therefore $AE = BE = 50\ m.$
Now from the rectangle $\text{BCDE}$ we have
$DE = BC = 10\ m.$
Therefore the length of $AD$ will be:
$AD = AE + DE = 50 + 10 = 60\ m.$
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