Question
Find $AD$
✓
Answer
In$\triangle AEB,$
$\frac{A E}{B E}=\tan 32^{\circ}$
$\Rightarrow A E=20 \times 0.6249=12.50 m$
$\therefore A D=A E+E D=12.50+5=17.50 m $
$\frac{A E}{B E}=\tan 32^{\circ}$
$\Rightarrow A E=20 \times 0.6249=12.50 m$
$\therefore A D=A E+E D=12.50+5=17.50 m $
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