Question
Find$:\text{AD}$
✓
Answer
From the right triangle $\text{ABD}$
$\cos A =\frac{Ac }{ AB } $
$\cos 60^{\circ}=\frac{ AD }{ AB }$
$ \frac{1}{2}=\frac{ AD }{12} $
$\text{AD} =\frac{12}{2} $
$=6\ cm$
$\cos A =\frac{Ac }{ AB } $
$\cos 60^{\circ}=\frac{ AD }{ AB }$
$ \frac{1}{2}=\frac{ AD }{12} $
$\text{AD} =\frac{12}{2} $
$=6\ cm$
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