Question
Find an anti derivative (or integral) of function by the method of inspection e2x .

Answer

We know that
$\frac{d}{d x}\left(e^{2 x}\right)=2 e^{2 x}$ 
$\Rightarrow \mathrm{e}^{2 \mathrm{x}}=\frac{1}{2} \frac{d}{d x}\left(e^{2 x}\right)$ 
$=\frac{d}{d x}\left(\frac{1}{2} e^{2 x}\right)$ 
Therefore, the anti-derivative of e2x is $\frac{1}{2} e^{2 x}$.

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