Question
Find angle $'A\ '$ if:
✓
Answer
From the figure we have,
$ \tan A =\frac{\text { Perpendicular }}{\text { Base }}$
$\tan A =\frac{10 \sqrt{3}}{10}$
$\tan A =\sqrt{3}$
$\tan A =\tan 60^{\circ}$
$\therefore A =60^{\circ}$
$ \tan A =\frac{\text { Perpendicular }}{\text { Base }}$
$\tan A =\frac{10 \sqrt{3}}{10}$
$\tan A =\sqrt{3}$
$\tan A =\tan 60^{\circ}$
$\therefore A =60^{\circ}$
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