Question
Find $A^{\top}$, if

$A=\left[\begin{array}{ccc}2 & -6 & 1 \\ -4 & 0 & 5\end{array}\right]$

Answer

$A=\left[\begin{array}{lllll}-4 & 0 & 52 & -6 & 1\end{array}\right]$

$\therefore A^{\top}=\left[\begin{array}{cc}2 & -4 \\ -6 & 0 \\ 1 & 5\end{array}\right]$

[Note: Answer given in the textbook is $A^{\top}=\left[\begin{array}{cc}2 & -4 \\ 6 & 0 \\ 1 & 5\end{array}\right]$. However, as per our calculation it

is $\left.A^{\top}=\left[\begin{array}{cc}2 & -4 \\ -6 & 0 \\ 1 & 5\end{array}\right] \cdot\right]$

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