Find d y d x if y = ^ –1 (2 x 1+x^ 2 ) - Vidyadip

Question

Find $\frac{d y}{d x}$ if $y = \sin^{–1} \left(\frac{2 x}{1+x^{2}}\right)$

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Answer

Here, y = $sin^{-1}(\frac{2x}{1+x^2})$
Let $x = tan A$
then, $A = \tan^{-1}x$
$\Rightarrow \frac{d A}{d x}=\frac{1}{1+x^{2}}$
y = $\sin ^{-1}\left(\frac{2 \tan A}{1+\tan ^{2} A}\right)$
Also, we know $\left[\sin 2 A=\frac{2 \tan A}{1+\tan ^{2} A}\right]$
$\Rightarrow y = sin^{-1} (sin2A)$
$\Rightarrow y = 2A$
$\Rightarrow$ $\frac{d y}{d x}=\frac{dy}{dA} \times\frac{dA}{dx}=2 \frac{d A}{d x}$ ...[By chain rule]
$\Rightarrow$ $\frac{d y}{d x}=\frac{2}{1+x^{2}}$

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