Question
Find $\frac{d y}{d x}$ if, :
$
y=\log (\log x)
$

Answer

Given $y=\log (\log x)$
Let $u =\log x$
Then $y =\log u$
$
\therefore \frac{d y}{d u}=\frac{d}{d u}(\log u)
$
$
\begin{aligned}
& =\frac{1}{u}=\frac{1}{\log x} \\
& \text { and } \frac{d u}{d x}=\frac{d}{d x}(\log x)=\frac{1}{x} \\
& \therefore \frac{d y}{d x}=\frac{d y}{d u} \cdot \frac{d u}{d x}=\frac{1}{\log x} \times \frac{1}{x} \\
& =\frac{1}{x \log x} \text {. } \\
\end{aligned}
$

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