Question
Find $\frac{{dy}}{{dx}}$ if  $2x + 3y = \sin y$

Answer

Given: $2x + 3y = \sin y$

$\Rightarrow \frac{d}{{dx}}\left( {2x} \right) + \frac{d}{{dx}}\left( {3y} \right) = \frac{d}{{dx}}\sin y$   

$\Rightarrow 2 + 3\frac{{dy}}{{dx}} = \cos y\frac{{dy}}{{dx}}$

$\Rightarrow - \cos y\frac{{dy}}{{dx}} + 3\frac{{dy}}{{dx}} = - 2$

$\Rightarrow - \frac{{dy}}{{dx}}\left( {\cos y - 3} \right) = - 2$

$\Rightarrow \frac{{dy}}{{dx}} = \frac{2}{{\cos y - 3}}$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free