Question
Find $\frac{d y}{d x}$ if : $\mathrm{y}=\frac{1+x}{2+x}$

Answer

$
y=\frac{1+x}{2+x}
$
Differentiating w.r.t. $x$, we get
$
\begin{aligned}
\frac{\mathrm{d} y}{\mathrm{~d} x} & =\frac{\mathrm{d}}{\mathrm{d} x}\left(\frac{1+x}{2+x}\right) \text { } \\
& =\frac{(2+x) \frac{\mathrm{d}}{\mathrm{d} x}(1+x)-(1+x) \frac{\mathrm{d}}{\mathrm{d} x}(2+x)}{(2+x)^2} \\
& =\frac{(2+x)(0+1)-(1+x)(0+1)}{(2+x)^2 \text { }} \\
\frac{\mathrm{d} y}{\mathrm{~d} x} & =\frac{(2+x)-(1+x)}{(2+x)^2}=\frac{2+x-1-x}{(2+x)^2}=\frac{1}{(2+x)^2}
\end{aligned}
$

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