Gujarat BoardEnglish MediumSTD 12 ScienceMathsIntegrals1 Mark
Question
Find: $\int \cos ^{2} x d x$
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Answer
cos 2x = 2 cos2 x - 1 $\cos ^{2} x=\frac{1+\cos 2 x}{2}$ Therefore, $\int \cos ^{2} x d x=\frac{1}{2} \int(1+\cos 2 x) d x=\frac{1}{2} \int d x+\frac{1}{2} \int \cos 2 x d x$ = $\frac{x}{2}+\frac{1}{4} \sin 2 x+C$
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