Question
Find $\int e^{x} \sin x d x$ 

Answer

Take ex as the first function and sin x as second function.
Using Integrating by parts, we have
$\mathrm{I}=\int e^{x} \sin x d x=e^{x}(-\cos x)+\int e^{x} \cos x d x$ 
= -ex cos x + $I_1$ ......(i)
Taking ex and cos x as the first and second functions, respectively, in $I_1$, we get
$I_{1}=e^{x} \sin x-\int e^{x} \sin x d x$ 
Substituting the value of $I_1$ in (i), we get
$I$ = -ex cos x + ex sin x - $I$  
$\Rightarrow~2I$ = ex (sin x - cos x)
Hence, $I=\int e^{x} \sin x d x=\frac{e^{x}}{2}(\sin x-\cos x)+C$

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