Rajasthan BoardEnglish MediumSTD 12 ScienceMATHSIntegrals1 Mark
Question
Find $\int \sqrt{x^{2}+2 x+5} d x$
✓
Answer
Note that $\int \sqrt{x^{2}+2 x+5} d x=\int \sqrt{(x+1)^{2}+4} d x$ Put x + 1 = y, so that dx = dy. Then $\int \sqrt{x^{2}+2 x+5} d x=\int \sqrt{y^{2}+2^{2}} d y$ = $\frac{1}{2} y \sqrt{y^{2}+4}+\frac{4}{2} \log |y+\sqrt{y^{2}+4}|+C$ = $\frac{1}{2}(x+1) \sqrt{x^{2}+2 x+5}+2 \log |x+1+\sqrt{x^{2}+2 x+5}|+\mathrm{C}$
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