Question
Find: $\int\frac{2x + 1}{(x^{2} + 1) (x^{2} + 4)}dx$

Answer

$\text{Let I} = \int\frac{\text{2x} + 1}{(\text{x}^{2} + 1) (\text{x}^{2} + 4)}\text{dx}$
$\text{Let}\frac{\text{2x} + 1}{(\text{x}^{2} + 1) (\text{x}^{2} + 4)} = \frac{\text{Ax + B}}{\text{x}^{2} + 1} + \frac{\text{Cx + D}}{\text{x}^{2} + 4}$
$\text{Getting A} = \frac{2}{3}, \text{B} = \frac{1}{3}, \text{C} = \frac{-2}{3} ,\text{D} = \frac{-1}{3}$
$\therefore\text{I} = \frac{2}{3}\int\frac{\text{x}}{\text{x}^{2} + 1}\text{dx}+\frac{1}{3}\int\frac{\text{1}}{\text{x}^{2} + 1}\text{dx}+ \frac{-2}{3}\int\frac{\text{xdx}}{\text{x}^{2} + 4}\text{dx} + \frac{-1}{3}\int\frac{\text{dx}}{\text{x}^{2} + 4}$
$= \frac{1}{3}\log|\text{x}^{2} + 1| + \frac{1}{3} \tan^{-1} \text{x} -\frac{1}{3}\log|\text{x}^{2} + 4| -\frac{1}{6}\tan^{-1}\frac{\text{x}}{2} + \text{C}$

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