Question
Find $k$ of the given figure.
✓
Answer
In the fig.,
$ k+2 k+3 k+42^{\circ}=360^{\circ} $.......(Angles at a point)
$ \Rightarrow 6 \mathrm{k}+42^{\circ}=360^{\circ} $
$ \Rightarrow 6 \mathrm{k}=360^{\circ}-42^{\circ}=318^{\circ} $
$ \Rightarrow \mathrm{k}=\frac{318^{\circ}}{6}=53^{\circ} $
$ \therefore \mathrm{k}=53^{\circ} $
$ k+2 k+3 k+42^{\circ}=360^{\circ} $.......(Angles at a point)
$ \Rightarrow 6 \mathrm{k}+42^{\circ}=360^{\circ} $
$ \Rightarrow 6 \mathrm{k}=360^{\circ}-42^{\circ}=318^{\circ} $
$ \Rightarrow \mathrm{k}=\frac{318^{\circ}}{6}=53^{\circ} $
$ \therefore \mathrm{k}=53^{\circ} $
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