Question
Find $\lim\limits_{\text{x}\rightarrow0}\text{f}(\text{x})$ and $\lim\limits_{\text{x}\rightarrow1}\text{f}(\text{x})$, where $\text{f}(\text{x})=\begin{cases}2\text{x}+3,& x \leq 0\\3(\text{x}+1), & x > 0\end{cases}$

Answer

The given function is $\text{f}(\text{x})=\begin{cases}2\text{x}+3,& x \leq 0\\3(\text{x}+1), & x > 0\end{cases}$ $\lim\limits_{\text{x}\rightarrow0^-}\text{f}(\text{x})=\lim\limits_{\text{x}\rightarrow0}[2\text{x}+3]=2(0)+3=3$ $\lim\limits_{\text{x}\rightarrow0^+}\text{f}(\text{x})=\lim\limits_{\text{x}\rightarrow0}[3(\text{x}+1)]=3(0+1)=3$ $\therefore\lim\limits_{\text{x}\rightarrow0^-}\text{f}(\text{x})=\lim\limits_{\text{x}\rightarrow0^+}\text{f}(\text{x})=\lim\limits_{\text{x}\rightarrow0}\text{f}(\text{x})=3$ $\lim\limits_{\text{x}\rightarrow1^-}\text{f}(\text{x})=\lim\limits_{\text{x}\rightarrow1^+}3(\text{x}+1)=3(1+1)=6$ $\lim\limits_{\text{x}\rightarrow1^+}\text{f}(\text{x})=\lim\limits_{\text{x}\rightarrow1^+}3(\text{x}+1)=3(1+1)=6$ $\therefore\lim\limits_{\text{x}\rightarrow1^-}\text{f}(\text{x})=\lim\limits_{\text{x}\rightarrow1^+}\text{f}(\text{x})=\lim\limits_{\text{x}\rightarrow1}\text{f}(\text{x})=6$

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