Question
Find $\lim\limits_{\text{x}\rightarrow1^+}\frac{1}{\text{x}-1}.$

Answer

$\lim\limits_{\text{x}\rightarrow1^+}\frac{1}{(\text{x}-1)}=\lim\limits_{\text{h}\rightarrow0}\frac{1}{(1+\text{h}-1)}=\lim\limits_{\text{h}\rightarrow0}\frac{1}{\text{h}}=\infty$

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