Question
Find $\lim\limits_{\text{x}\rightarrow1^+}\frac{1}{\text{x}-1}.$
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$\left[\frac{x}{2}\right]+\left[\frac{x}{3}\right]=\frac{5 x}{6}$
$f(x)=\ln (x-5)$
$\ln 1=0$
$\frac{4+3 i}{1-i}$