Question
Find $\lim\limits_{\text{x}\rightarrow3}\text{f(x)},$ where $\text{f(x)}=\begin{cases}4, & \text{if x}> 3\\\text{x}+1, &\text{if x} < 3\end{cases}.$
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$\frac{(2 n) !}{7 !(2 n-7) !}: \frac{n !}{4 !(n-4) !}=24: 1$