
- A$x = LiAlH_4 , y = NaBH_4$
- B$X = LiAlH_4 / AlCl_3 ,y = LiAlH_4$
- ✓$x = LiAlH_4 , y = LiAlH_4 /AlCl_3$
- D$x = H_2 /Ni,y = H_2 /Pt.$


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$Z{n^{2 + }}\,(aq)\, + \,2e\, \rightleftharpoons \,Zn\,(s)\,;\, - \,0.762\,V$
$C{r^{3 + }}\,(aq)\, + \,3e\, \rightleftharpoons \,Cr(s)\,;\, - \,0.740\,\,V$
$2{H^ + }\,(aq)\, + \,2e\, \rightleftharpoons \,{H_2}(g)\,;\,\,\,0.00\,\,\,V$
$F{e^{3 + }}\,(aq)\, + \,e\, \rightleftharpoons \,F{e^{2 + }}(aq)\,;\,\,\,0.770\,\,\,V$
Which is the strongest reducing agent ?
$(I)$ $I.P.$ of $O(g)$ is less than $I.P.$ of $O_{\left( g \right)}^ - $
$(II)$ $I.P.$ of $Ne(g)$ is greater than $I.P$. of $Ne_{\left( g \right)}^ + $
$(III)$ $E.A.$ of $O_{\left( g \right)}^ + $ is greater than $E.A.$ of $O(g)$
$(IV)$ $I.P.$ of $N(g)$ is greater than $I.P.$ of $N_{\left( g \right)}^ + $
[Atomic number: $S =16, C 1=17, I =53$ and $Xe =54$ ]
The above reaction is classified as