Question
Find n if ${ }^6 P_2=n\left({ }^6 C_2\right)$

Answer

$\begin{array}{ll} & { }^6 P _2=n\left({ }^6 C _2\right) \\ \therefore \quad & \frac{6 !}{(6-2) !}=n \frac{6 !}{2 !(6-2) !} \\ \therefore \quad & \frac{6 !}{4 !}=n \frac{6 !}{2 ! 4 !} \\ \therefore \quad & n=2 !=2 \times 1=2\end{array}$

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