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Permutations and Combinations (p-2) — Maths (commerce) STD 11 Commerce / Arts — Question

Maharashtra BoardEnglish MediumSTD 11 Commerce / ArtsMaths (commerce)Permutations and Combinations (p-2)1 Mark
Question
Find $n$, iF : $(n+1) !=42 \times(n-1) !$

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Answer

$
\begin{aligned}
& (n+1) !=42(n-1) ! \\
& \therefore(n+1) n(n-1) !=42(n-1) ! \\
& \therefore n^2+n=42 \\
& \therefore n(n+1)=6 \times 7
\end{aligned}
$
Comparing on both sides, we get
$
\therefore \mathrm{n}=6
$

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