Question
$\text{Find}\ |\vec{a}\ \times\vec{b}|,\ \text{if}\ \vec{a}=\hat{i}-7\hat{j}+7\hat{k}\ \text{and}\ \vec{b}=3\hat{i}-2\hat{j}+2\hat{k}.$
$\vec{a}\times\vec{b}=\begin{vmatrix}\hat{i}&\hat{j}&\hat{k}\\1&-7&7\\3&-2&2\end{vmatrix}$
Expanding along first row, $\vec{a}\times\vec{b}=\hat{i}\begin{vmatrix}-7&7\\-2&2\end{vmatrix}-\hat{j}\begin{vmatrix}1&7\\3&2\end{vmatrix}+\hat{k}\begin{vmatrix}1&-7\\3&-2\end{vmatrix}$ $=\hat{i}(-14+14)-\hat{j}(2-21)+\hat{k}(-2+21)$$=0\hat{i}+19\hat{j}+19\hat{k}$
$\therefore\ \ \Big|\vec{a}\times\vec{b}\Big|=\sqrt{(0)^2+(19)^2+(19)^2}=\sqrt{2(19)^2}=19\sqrt{2}$Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| Xi | 0 | 1 | 2 |
| Pi | 3c3 | 4c - 10c2 | 5c - 1 |
Where c > 0
Find:
$\text{P}(1<\text{X}\leq2)$| $\text{X}=\text{x}_\text{i}:$ | $1$ | $2$ | $3$ |
| $\text{P}(\text{X}=\text{x}_\text{i}):$ | $\frac{1}{4}$ | $\frac{1}{8}$ | $\frac{5}{8}$ |