Question
Find out the EAN of
(a) $\left[ Zn \left( NH _3\right)_4\right]^{2+}$
(b) $\left[ Fe ( CN )_6\right]^{4+}$
(a) $\left[ Zn \left( NH _3\right)_4\right]^{2+}$
(b) $\left[ Fe ( CN )_6\right]^{4+}$
✓
Answer
(a) For the complex ion, $\left[ Zn \left( NH _3\right)_4\right]^{2+}$ :
Atomic number of $Zn = Z =30$
Charge on metal ion $=+2$
$\therefore$ Number of electrons lost by Zn atom $= X =2$ Total number of electrons donated by $4 NH _2{ }^3$
ligands $= Y =2 \times 4=8$
EAN $=Z-X+Y$
$=30-2+8$
$=36$ (Note : This is atomic number of the nearest inert element $3_6 Kr$.)
(b) For the complex ion, $[ Fe ( CN )]^{4-}$ :
For $Fe , Z =26$ (Atomic number)
$X=2$ (Due to +2 charge on Fe )
$Y =12$ (Due to $6 CN ^{-}$ligands)
$\therefore E A N=Z-X+Y$
$=26-2+12$
$=36$
Atomic number of $Zn = Z =30$
Charge on metal ion $=+2$
$\therefore$ Number of electrons lost by Zn atom $= X =2$ Total number of electrons donated by $4 NH _2{ }^3$
ligands $= Y =2 \times 4=8$
EAN $=Z-X+Y$
$=30-2+8$
$=36$ (Note : This is atomic number of the nearest inert element $3_6 Kr$.)
(b) For the complex ion, $[ Fe ( CN )]^{4-}$ :
For $Fe , Z =26$ (Atomic number)
$X=2$ (Due to +2 charge on Fe )
$Y =12$ (Due to $6 CN ^{-}$ligands)
$\therefore E A N=Z-X+Y$
$=26-2+12$
$=36$
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