Question
Find p(0), p(1) and p(2) for the polynomial: p(x) = (x – 1)(x + 1)
✓
Answer
p(x) = (x – 1)(x + 1)
$\therefore$ p(0) = (0 – 1)(0 + 1) = (–1)(1) = –1
p(1) = (1 – 1)(1 + 1) = (0)(2) = 0,
p(2) = (2 – 1)(2 + 1) = (1)(3) = 3
$\therefore$ p(0) = (0 – 1)(0 + 1) = (–1)(1) = –1
p(1) = (1 – 1)(1 + 1) = (0)(2) = 0,
p(2) = (2 – 1)(2 + 1) = (1)(3) = 3
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
A shopkeeper has one spherical laddoo of radius 5cm. With the same amount of material, how many laddoos of radius 2.5cm can be made?
What is the possible expression for the dimension of the cuboid whose volume is $12k{y^2} + 8ky - 20k$
→Define the following terms:
Plane.
Plane.
In figure, rays AB and CD intersect at O.
Determine y when x = 60°.
Determine y when x = 60°.
Factorise : $8(3a - 2b)^2 - 10(3a - 2b)$
→If $f(x) = 2x^3 - 13x^2 + 17x + 12,$ Find: $f(2)$
→Which pair of lines in the below figure is parallel? Give reasons.
The mean score of 25 observation is 80 and the mean score of another 55 obervations is 60. Determine the mean score of the whole set of observations.
In the adjoining figure, ABC and ABD are two triangles on the same base AB. If line segment CD is
bisected by AB at O, show that $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{ABD}).$
→bisected by AB at O, show that $\text{ar}(\triangle\text{ABC})=\text{ar}(\triangle\text{ABD}).$