Question
Find $p(0), p(1)$ and $p(2)$ for the polynomial: $p(x)=x^3$
✓
Answer
$p(x)=x^3$
$\therefore p(0)=(0)^3=0,$
$p(1)=(1)^3=1$
$p(2)=(2)^3=8$
$\therefore p(0)=(0)^3=0,$
$p(1)=(1)^3=1$
$p(2)=(2)^3=8$
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