Find p(0), p(1) and p(2) for the polynomial: p(y)=y^2-y+1 - Vidyadip

Question

Find $p(0), p(1)$ and $p(2)$ for the polynomial: $p(y)=y^2-y+1$

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Answer

$p(y)=y^2-y+1$
$\therefore p(0)=(0)^2-(0)+1=1$
$p(1)=(1)^2-(1)+1=1$
$p(2)=(2)^2-(2)+1=4-2+1=3$

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