Question
Find $p(0), p(1), p(-2)$ for the following polynomial: $p(y) = (y + 2)(y - 2)$
✓
Answer
Given, polynomial is $p(y) = (y + 2)(y - 2)$
On putting $y = 0, 1$ and $-2$, respectively in Eq. $(i),$
We get $p(0) = (0 + 2)(0 - 2)= -4 $
$p(1) = (1 + 2)(1 - 2) = 3 × (-1) = -3$ and
$p(-2) = (-2 + 2)(-2 - 2) = 0(-4) = 0$
Hence, the values of $p(0), p(1)$ and $p(-2)$ are respectively, $-4, -3$ and $0.$
On putting $y = 0, 1$ and $-2$, respectively in Eq. $(i),$
We get $p(0) = (0 + 2)(0 - 2)= -4 $
$p(1) = (1 + 2)(1 - 2) = 3 × (-1) = -3$ and
$p(-2) = (-2 + 2)(-2 - 2) = 0(-4) = 0$
Hence, the values of $p(0), p(1)$ and $p(-2)$ are respectively, $-4, -3$ and $0.$
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