Question
Find the additive inverse of:
$\frac{-18}{-13}$

Answer

$\frac{-18}{-13}=\frac{-18\times(-1)}{-13\times(-1)}=\frac{18}{13}$
$\therefore$ Additive inverse of $\frac{18}{13}=-\Big(\frac{18}{13}\Big)$
$=\frac{-18}{13}$

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