Question
Find the additive inverse of:$\frac{7}{-10}$

Answer

Additive inverse of a number $\frac{\text{a}}{\text{b}}$ is the number $-\frac{\text{a}}{\text{b}}$ Such that, $\frac{\text{a}}{\text{b}}+\Big(\frac{-\text{a}}{\text{b}}\Big)=0$ Therefore,$\frac{7}{-10}=\frac{7\times-1}{-10\times-1}$
$=\frac{7}{-10}$
Additive inverse of $\frac{-7}{10}$ is $\frac{7}{10}$

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