Question
Find the altitude of a parallelogram whose area is $=54 \mathrm{dm}^2$ and base is $12dm$.

Answer

We have,
Area of the given parallelogram $=54 \mathrm{dm}^2$
Base of the given parallelogram $=12 \mathrm{dm}$
Altitude of the given parallelogram $=\frac{\text { Area }}{\text { Base }}=\frac{54}{12} \mathrm{dm}=4.5 \mathrm{dm}$

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