Question
Find the angle between the lines x = a and by + c = 0.

Answer

$\text{x}=\text{a}$
$\Rightarrow\text{m}_1=\frac{1}{0}$
$\text{by}+\text{c}=0$
$\text{y}=\frac{-\text{c}}{\text{b}}$
$\text{m}_2=0$
Comparing with y = mx + c
Then, putting in
$\tan\theta=\Big|\frac{\text{m}_1-\text{m}_2}{1+\text{m}_1\text{m}_2}\Big|$
$=\Bigg|\frac{\frac{1}{0}-0}{1+\frac{1}{0}\times0}\Bigg|$
$=\frac{1}{0}=\infty$
$\Rightarrow\theta=90^\circ$

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