MCQ
Find the angle which is $56^\circ$ more than its complement.
- A$22^\circ$
- B$63^\circ$
- ✓$73^\circ$
- D$33^\circ$
✓
Answer
Correct option: C.
$73^\circ$
Let unknown angle be $x^\circ .$
$\therefore$ Complement of $x = 90^\circ - x$
Acc to question,
$(90 - x)^\circ - x = 56^\circ $
$90^\circ - 2x = 56^\circ $
$-2x = -34^\circ $
$x = 17^\circ $
$\therefore (90 - x) = 90^\circ - 17^\circ = 73^\circ $
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